# Doubly exponential growth of 3-uniform Ramsey numbers Colour every triple of an $m$-element set red or blue: how large must $m$ be to guarantee $n$ points whose triples all have the same colour? The answer lies between $2^{cn^2}$ and $2^{2^n}$, an enormous gap. Erdős, Hajnal and Rado conjectured that the truth is doubly exponential, and Erdős offered \$500 for a proof. ## Problem Let $R_3(n)$ be the least $m$ such that in every 2-colouring of the triples of an $m$-element set there are $n$ elements all of whose $\binom n3$ triples have the same colour. Is there a constant $c>0$ such that $$ R_3(n)\ge 2^{2^{cn}}\quad\text{for all large } n\,? $$ ## Background For graphs, the Ramsey number $R(n)$ grows exponentially in $n$. For triples, Erdős, Hajnal and Rado (1965) proved $$ 2^{cn^2}0$. The lower bound comes from a random colouring, and no better construction is known for two colours. The question is a special case of the general problem of how fast hypergraph Ramsey numbers grow, and it is the key case: the Erdős–Hajnal stepping-up lemma turns lower bounds for $3$-uniform hypergraphs into lower bounds one exponential higher for each further uniformity. A doubly exponential lower bound for $R_3(n)$ would therefore give lower bounds for every uniformity $k\ge3$ that match the known upper bounds, a tower of height $k$, up to the constant in the top exponent. Erdős listed it among the combinatorial problems he most wanted to see solved. ## What is known - **Two colours.** The bounds $2^{cn^2}