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The Erdős–Szekeres happy ending problem

Prove that any 2^{n−2}+1 points in general position in the plane contain a convex n-gon; open from n = 7 on.

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The Erdős–Szekeres happy ending problem

Among any five points in the plane with no three on a line, four form a convex quadrilateral. Erdős and Szekeres asked how many points in general position force a convex nn-gon, and conjectured the answer 2n−2+12^{n-2}+1. Erdős named it the happy ending problem because it led to the marriage of George Szekeres and Esther Klein, who first raised it.

Problem

Let f(n)f(n) be the smallest integer such that any f(n)f(n) points in the plane, no three on a line, contain nn points that are the vertices of a convex nn-gon. Prove that

f(n)=2n−2+1for all n≥3.f(n)=2^{n-2}+1\quad\text{for all } n\ge3.

Erdős offered $500 for a proof (and $100 for a disproof); Graham later offered $1000 for a proof.

Background

Esther Klein observed in 1931 that f(4)=5f(4)=5, and Turán and Makai showed f(5)=9f(5)=9. Erdős and Szekeres proved in 1935 that f(n)f(n) exists, with f(n)≤(2n−4n−2)+1f(n)\le\binom{2n-4}{n-2}+1, and in 1960 they constructed sets of 2n−22^{n-2} points with no convex nn-gon, giving f(n)≥2n−2+1f(n)\ge 2^{n-2}+1. Szekeres and Peters (2006) settled f(6)=17f(6)=17 by a computer search. For a long time all improvements of the upper bound were of the form 4(1+o(1))n4^{(1+o(1))n}.

What is known

  • Small values. f(4)=5f(4)=5, f(5)=9f(5)=9, and f(6)=17f(6)=17 (Szekeres and Peters, 2006), all agreeing with the conjecture.
  • Upper bound. Suk (2017) proved f(n)≤2n+o(n)f(n)\le 2^{n+o(n)}, so the conjecture is correct in the exponent; Holmsen, Mojarrad, Pach and Tardos (2020) refined this to f(n)≤2n+O(nlog⁡n)f(n)\le 2^{n+O(\sqrt{n\log n})}.
  • Lower bound. The Erdős–Szekeres construction gives f(n)≥2n−2+1f(n)\ge 2^{n-2}+1, which is conjectured to be exact.

What would count as progress

  • The value f(7)f(7): either a proof that 3333 points in general position always contain a convex heptagon (presumably computer-assisted, with a checkable certificate such as a SAT proof), or 3333 points with no convex heptagon, which would disprove the conjecture and can be verified directly.
  • An upper bound of the form f(n)≤2n+O(log⁡n)f(n)\le 2^{n+O(\log n)}, or f(n)≤C⋅2nf(n)\le C\cdot 2^{n}.
  • A proof of the conjecture in full.
  • A formal proof against the Lean statement in formal-conjectures.

References

  1. P. Erdős and G. Szekeres, A combinatorial problem in geometry, Compos. Math. 2 (1935), 463–470. numdam.org
  2. G. Szekeres and L. Peters, Computer solution to the 17-point Erdős–Szekeres problem, ANZIAM J. 48 (2006), 151–164. doi:10.1017/S144618110000300X
  3. A. Suk, On the Erdős–Szekeres convex polygon problem, J. Amer. Math. Soc. 30 (2017), 1047–1053. doi:10.1090/jams/869
  4. A. F. Holmsen, H. N. Mojarrad, J. Pach and G. Tardos, Two extensions of the Erdős–Szekeres problem, J. Eur. Math. Soc. 22 (2020), 3981–3995. doi:10.4171/JEMS/1000

Source

Imported from Erdős Problems 107, curated by Thomas Bloom. Open according to the source as of 2026-10-20. The statement above is written in our own words; see the source for the original wording, history and discussion.